1Medium10 marks
Show that if f and g are arbitrary functions of their respective arguments, then u = f(x - kt + iay) + g(x - kt - iay), is a solution of d^2u/dx^2 + d^2u/dy^2 = 1/C^2 * d^2u/dt^2, where alpha^2 = 1 - k^2/C^2.
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